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# Rule that checks for repeated words
# (c) 2003,2004 Daniel Naber <daniel.naber@t-online.de>
#
#$rcs = ' $Id$ ' ;
#
# This library is free software; you can redistribute it and/or
# modify it under the terms of the GNU Lesser General Public
# License as published by the Free Software Foundation; either
# version 2.1 of the License, or (at your option) any later version.
#
# This library is distributed in the hope that it will be useful,
# but WITHOUT ANY WARRANTY; without even the implied warranty of
# MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the GNU
# Lesser General Public License for more details.
#
# You should have received a copy of the GNU Lesser General Public
# License along with this library; if not, write to the Free Software
# Foundation, Inc., 59 Temple Place, Suite 330, Boston, MA 02111-1307 USA
import os
import re
import sys
import Rules
import Tools
class enWordRepeatRule(Rules.Rule):
"""Rule that checks if a word is repeated, even if one
word is uppercase and the other one is lowercase."""
punct = re.compile("([,:;]+)") # copied from Tagger.Text()
def __init__(self):
Rules.Rule.__init__(self, "WORD_REPEAT", "A word was repeated", 0, None)
return
def match(self, tagged_words, chunks, position_fix=0, line_fix=0, column_fix=0):
matches = []
text_length = 0
i = 0
line_breaks = 0
column = 0
while 1:
org_word = tagged_words[i][0]
line_breaks_cur = Tools.Tools.countLinebreaks(org_word)
if line_breaks_cur > 0:
column = 0
line_breaks = line_breaks + line_breaks_cur
if i >= len(tagged_words)-2:
break
org_tag = tagged_words[i][2]
if org_tag == "CRD":
# ignore numbers like "5,000,000"
i = i + 1
continue
if org_word and self.punct.match(org_word):
# ignore punctuation
i = i + 1
continue
org_word_next = tagged_words[i+2][0]
text_length = text_length + len(org_word)
if tagged_words[i][1] == None:
# ignore whitespace
if line_breaks_cur == 0:
column = column + len(org_word)
i = i + 1
continue
whitespace_length = len(tagged_words[i+1][0])
if line_breaks_cur == 0:
column = column + len(org_word)
if org_word.lower() == org_word_next.lower():
matches.append(Rules.RuleMatch(self.rule_id,
text_length+position_fix,
text_length+whitespace_length+len(org_word_next)+position_fix,
line_breaks+line_fix, column+column_fix,
"<message>You repeated a word. Maybe you should <em>remove</em> one "+
"of the words?</message>", org_word))
i = i + 1
return matches
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